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14 April, 14:24

If 54.9 L of an ideal gas is cooled from 64 degrees C to 7 degrees C, what will the volume of the gas become?

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  1. 14 April, 16:52
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    Volume = 45.62L

    Explanation:

    Data;

    V1 = 54.9L

    T1 = 64°C = (64 + 273.15) k = 337.15K

    T2 = 7°C = (7 + 273.15) k = 280.15K

    V2 = ?

    From Charles law,

    The volume of a fixed mass of gas is directly proportional to its temperature provided that pressure remains constant

    V = KT, K = V / T = V1 / T1 = V2 / T2 = V3 / T3 = ... = Vn / Tn

    (54.9 / 337.15) = (V2 / 280.15)

    V2 = (54.9 * 280.15) / 337.15

    V2 = 45.618L

    V2 = 45.62L
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