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14 April, 07:01

What is the pH of the solution obtained by mixing 30 mL of. 25 M HCL in 30 mL of. 125 M NaOH

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  1. 14 April, 09:54
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    pH after mixing = 1.2

    Explanation:

    HCl + NaOH = > NaCl + H₂O

    Will show only the reactants for the solution set ...

    Given 30ml (0.25M HCl) + 30ml (0.125M NaOH)

    => 0.030 (0.25) mole HCl + 0.030 (0.125) mole NaOH

    => 0.0075mole HCl + 0.00345mol NaOH

    moles HCl neutralized = moles NaOH added into solution (1:1 reaction ratio)

    => (0.0075 - 0.00375) mol HCl remains in excess in 60ml of solution

    => (0.00375mol/0.060L) HCl = 0.0625M in HCl

    pH = - log[HCl] = - log[H⁺] = - log (0.0625) = - (-1.2) = 1.2
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