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29 July, 09:09

A tank of oxygen has a volume of 1650 L. The temperature of the gas inside is 35? C. If there are 9750 moles of oxygen in the tank what is the pressure in psi?

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  1. 29 July, 09:53
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    2192.64 PSI.

    Explanation:

    From the general law of ideal gases:

    PV = nRT.

    where, P is the pressure of the gas in atm.

    V is the volume of the container in L (V = 1650 L).

    n is the no. of moles of the gas in mol (n = 9750 mol).

    R is the general gas constant (R = 0.082 L. atm/mol. K).

    T is the temperature of the gas in (T = 35°C + 273 = 308 K).

    ∴ P = nRT/V = (9750 mol) (0.082 L. atm/mol. K) (308 K) / (1650 L) = 149.2 atm.

    To convert from atm to PSI:

    1 atm = 14.696 PSI.

    ∴ P = 149.2 atm x (14.696 PSI/1.0 atm) = 2192.64 PSI.
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