Aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water. Suppose 34. g of hydrochloric acid is mixed with 9.30 g of sodium hydroxide. Calculate the minimum mass of hydrochloric acid that could be left over by the chemical reaction. Round your answer to significant digits.

25.51g

Explanation:

We'll begin by writing a balanced equation for the reaction. This is illustrated below:

HCl (aq) + NaOH (aq) - > NaCl (aq) + H2O (l)

Next, let us calculate the molar masses of HCl and NaOH. This is illustrated below:

Molar Mass of HCl = 1 + 35.5 = 36.5g/mol

Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol

From the equation above,

36.5g of HCl reacted with 40g of NaOH.

Therefore Xg of HCl will react with with 9.3g of NaOH i. e

Xg of HCl = (36.5 x 9.3) / 40

Xg of HCl = 8.49g

Therefore, 8.49g of HCl was used up in the reaction.

To obtain the left over Mass of HCl, we'll subtract the mass used in the reaction from the mass given from the question. This is illustrated below:

Mass of HCl from the question = 34g

Mass of HCl used in the reaction = 8.49g

The left over mass of HCl = 34 - 8.49

The left over mass of HCl = 25.51g