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31 July, 22:40

A sample of aluminum metal absorbs 8.32 J of heat, upon which the temperature of the sample increases from 23.2 degrees C to 30.5 degrees C. Since the specific heat capacity of aluminum is 0.90 J/g-K, the mass of the sample is what in grams?

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  1. 1 August, 00:47
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    Given:

    8.32 J of heat

    from 23.2 degrees C to 30.5 degrees C

    heat capacity of aluminum is 0.90 J/g-K

    Required:

    m in grams

    Solution:

    H = mCpT

    (8.32 J) = m (0.90 J/g-K) (30.5 - 23.2) K

    m = 1.27g
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