How many moles are in 43.9 L of oxygen

Answer: 2 mol

Explanation:

- According to the ideal gas law, One mole of an ideal gas at STP (standard temperature and normal pressure) occupies 22.4 liters.

- Using cross multiplication,

1 mol of (O2) → 22.4 L

? → 43.9 L

Therefore, the number of moles of oxygen in 43.9 L = (43.9 * 1) / 22.4 = 1.96 mol≈ 2 mol ...