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7 August, 00:54

Describe in detail how to prepare 500 ml of a 2.5 m calcium chloride solutiion

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  1. 7 August, 02:27
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    No. of moles of calcium chloride = molarity * volume of solution in L

    No. of moles of calcium chloride = 2.5 * 0.5 = 1.25 mole

    No. of moles of calcium chloride = mass of calcium chloride / molar mass of calcium chloride

    1.25 mole = mass of calcium chloride / 110.98 g/mol

    mass of calcium chloride = 1.25 * 110.98 = 139 g
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