You are given an unknown sample that when treated with hydrochloric acid forms a precipitate. After decantation, you add boiling water to the solid; some of the solid disappears. You decant the solution and add a few drops of K2CrO4; a yellow solid appears. To the solid left from the addition of boiling water, you add ammonium hydroxide and centrifuge the product. You then decant the liquid and add concentrated nitric acid to the solution until acidic; a white precipitate forms.

Which group 1 cations were present in your unknown?

Question

Chemistry

Reece Costa

29 July, 15:27

You are given an unknown sample that when treated with hydrochloric acid forms a precipitate. After decantation, you add boiling water to the solid; some of the solid disappears. You decant the solution and add a few drops of K2CrO4; a yellow solid appears. To the solid left from the addition of boiling water, you add ammonium hydroxide and centrifuge the product. You then decant the liquid and add concentrated nitric acid to the solution until acidic; a white precipitate forms.

Which group 1 cations were present in your unknown?

+1

Answers (1)

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Francis Maddox · Answer 1

Part B : Hg

Part C : Ag

Explanation:

When we added ammonium hydroxide to the solid remains after addition hot water, AgCl dissolve due to the formation of soluble complex [Ag (NH3) 2] + and Hg2Cl2 gives black precipitate with ammonium hydroxide due to formation of elemental mercury.

Black precipitate is not formed upon addition of amonium hydroxide to the precipitate remains after addition of hot water, so Hg22 + is shown not to be present.

The precepite remains after addition of hot water is dissolved by the addition of ammonium hydroxide, so Ag + may be present. The presence of Ag + is not confiremed by K2CrO4 test.