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15 September, 13:51

I'm trying to learn molarity problems on my own (online schooling is terrible), I don't need the answer for the following problem as much as I need the process of solving it explained

How many L of solution are present if 100g NaCl has been dissolved in water to make a 2.50M solution?

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  1. 15 September, 15:17
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    0.68L

    Explanation:

    First, let us calculate the number of mole in 100g of NaCl. This is illustrated below:

    Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

    Mass of NaCl = 100g

    Number of mole of NaCl = ?

    Number of mole = Mass/Molar Mass

    Number of mole of NaCl = 100/58.5

    Number of mole of NaCl = 1.709 mole

    Now we can find the volume of the solution as follow:

    Mole = 1.709 mole

    Molarity = 2.50M

    Volume = ?

    Molarity = mole / Volume

    Volume = mole / Molarity

    Volume = 1.709/2.5

    Volume = 0.68L
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