The specific heat for liquid ethanol is 2.46 J / (g•°C). When 210 g of ethanol is cooled from

50 °C to 5 °C, the surrounding 7.80 x 103 g of air absorbs the heat. The specific heat of

air is 1.01J / (9•°C). What is the change in air temperature, assuming all the heat released

by the ethanol is absorbed by the air?

Question

Chemistry

Cyrus Swanson

15 January, 17:44

The specific heat for liquid ethanol is 2.46 J / (g•°C). When 210 g of ethanol is cooled from

50 °C to 5 °C, the surrounding 7.80 x 103 g of air absorbs the heat. The specific heat of

air is 1.01J / (9•°C). What is the change in air temperature, assuming all the heat released

by the ethanol is absorbed by the air?

+2

Answers (1)

Know the Answer?

Waylon · Answer 1

a) heat it from 23.0 to 78.3

q = (50.0 g) (55.3 °C) (2.46 J/g·°C) =

b) boil it at 78.3

(39.3 kJ/mol) (50.0 g / 46.0684 g/mol) =

c) sum up the answers from the two calculations above. Be sure to change the J from the first calc into kJ