A 4.00-gram sample of sodium chloride was added to a beaker containing 40.0 mL 0.033 M lead (II)
nitrate solution. Lead (II) chloride was precipitated according to the following reaction.
2NaCl (s) + Pb (NO3) 2 (aq) PbCl2 (s) + 2NaNO3 (aq)
Calculate the mass of lead (II) chloride that can be recovered. Pb = 207; Na = 23; Cl = 35.5; N = 14;
O = 16.
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