You have the equations:

2H2O (l) →2H2 (g) + O2 (g), △H=572 kJ

2N2 (g) + 3H2 (g) →2NH3 (g), △H=-138 kJ

2NO2 (g) + 7H2 (g) →2NH3 (g) + 4H2O (l), △H=-1.18103 kJ 2NO2 (g) →2N2 (g) + 2O2 (g), △H=□

What is the missing △H?

-1.38103 kJ

+99.0 kJ

+1.38 * 10³ kJ

-138 kJ

Question

Bailey Figueroa

22 October, 13:47

+5

Answers (1)

Know the Answer?

Teagan Mcguire · Answer 1

the answer is 99.0kJ

Explanation:

I took the test in chemistry

You have the equations:2H2O (l) →2H2 (g) + O2 (g), △H=572 kJ2N2 (g) + 3H2 (g) →2NH3 (g), △H=-138 kJ2NO2 (g) + 7H2 (g) →2NH3 (g) + 4H2O (l), △H=-1.18*103 kJ 2NO2 (g) →2N2 (g) + 2O2 (g), △H=□What is the missing △H?-1.38*103 kJ+99.0 kJ+1.38 * 10³ kJ-138 kJ