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15 December, 10:20

What is the molality of a solution in which 55g of sucrose are dissolved in 950mL of water?

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  1. 15 December, 12:26
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    0.169M

    Explanation:

    The following were obtained from the question:

    Mass of sucrose (C12H22O11) = 55g

    Volume of solution = 950 mL

    Next, we shall determine the number of mole of sucrose in 55g of sucrose. This is illustrated below:

    Mass of C12H22O11 = 55g

    Molar Mass of C12H22O11 = (12x12) + (22x1) + (16x11) = 144 + 22 + 176 = 342g/mol

    Number of mole = Mass/Molar Mass

    Number of mole C12H22O11 = 55/342 = 0.161 mole

    Next, we shall convert 950 mL to L. This is illustrated below:

    1000mL = 1L

    Therefore, 950mL = 950/1000 = 0.95L

    Now, we can calculate the molarity of the solution as follow:

    Molarity = mole / Volume

    Mole of C12H22O11 = 0.161 mole

    Volume = 0.95L

    Molarity = 0.161 / 0.95

    Molarity = 0.169M
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