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15 September, 17:32

When a sample of a gas was placed in a sealed container with a volume of 3.35L and heated to 105°C, the gas vaporized and the resulting pressure inside the container was 170.0kPa. How many moles of the gas was president?

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  1. 15 September, 17:43
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    181.12 moles

    Explanation:

    V = 3.35L

    T = 105°C = (105 + 273.15) K = 378.15K

    P = 170.0kPa = 170.0*10³Pa (1kPa = 1000Pa)

    R = 8.314J / mol. K

    n = ?

    From ideal gas equation,

    PV = nRT

    P = pressure of the gas

    V = volume of the gas

    n = number of moles

    R = ideal gas constant

    T = temperature of the gas

    PV = nRT

    n = PV / RT

    n = (170*10³ * 3.35) / (8.314 * 378.15)

    n = 569500 / 3144.317

    n = 181.12 moles
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