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29 November, 22:18

At standard temperature and pressure (0 ∘C and 1.00 atm), 1.00 mol of an ideal gas occupies a volume of 22.4 L. What volume would the same amount of gas occupy at the same pressure and 55 ∘C?

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  1. 30 November, 02:10
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    Answer:26.9L

    Explanation: this is Charles' law which states that the volume of a gas is directly proportional to the absolute temperature at contant pressure. The expression is V1/T1 = V2/T2

    Making V2 the subject of the formula we have

    V2 = V1 xT2/T1

    = 22.4 x 328/273

    = 26.9L
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