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26 February, 11:40

A sample of ammonia is found to occupy 0.250 L under laboratory conditions of 27 °C and 0.850 atm. Find the volume of this sample at 0 °C and 1.00 atm.

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  1. 26 February, 15:31
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    0.193 L

    Explanation:

    Step 1:

    Data obtained from the question.

    Initial Volume (V1) = 0.250 L

    Initial temperature (T1) = 27°C

    Initial pressure (P1) = 0.850 atm

    Final volume (V2) = ?

    Final temperature (T2) = 0°C

    Final pressure (P2) = 1.00 atm

    Step 2:

    Conversion of celsius temperature to Kelvin temperature.

    Temperature (Kelvin) = temperature (celsius) + 273

    Initial temperature (T1) = 27°C = 27°C + 273 = 300K

    Final temperature (T2) = 0°C = 0°C + 273 = 273K

    Step 3:

    Determination of the new volume of the sample of ammonia gas.

    The new volume can be obtain by using the general gas equation as shown below:

    P1V1/T1 = P2V2/T2

    0.850x0.250/300 = 1xV2/273

    Cross multiply to express in linear form

    300 x V2 = 0.850x0.250x273

    Divide both side by 300

    V2 = (0.850x0.250x273) / 300

    V2 = 0.193 L

    Therefore, the volume of the sample at 0 °C and 1.00 atm is 0.193 L
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