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28 March, 04:45

Calculate the enthalpy change for the thermite reaction: 2al (s) + fe2o3 (s) →2fe (s) + al2o3 (s), δh∘rxn=-850 kj when 4.00 mol of al undergoes the reaction with a stoichiometrically equivalent amount of fe2o3.

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  1. 28 March, 05:17
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    Given:

    Enthalpy change ΔH for the thermite reaction = - 850 kJ

    Moles of Al involved = 4

    To determine:

    Reaction enthalpy when 4 moles of Al reacts

    Explanation:

    The thermite reaction is-

    2Al (s) + Fe2O3 (s) → 2Fe (s) + Al2O3 (s)

    When 2 moles of Al react the enthalpy change is - 850 kJ

    therefore, when 4 moles of Al reacts, the change in enthalpy is-

    = 4 moles * (-850) kJ/2 moles = - 1700 kJ

    Ans: Enthalpy change is - 1700 kJ
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