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30 January, 13:28

A mineral contains only a metal, M, and sulfur. If analysis indicates that a 44.9 g sample of the mineral contains 2.1 g of M, what mass of M (g) is contained in 329 g of the mineral?

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Answers (2)
  1. 30 January, 16:43
    0
    15.38 g is the mass for M in the 329 g of sample

    Explanation:

    Mineral's formula: MS

    Our sample weighs 44.9 g

    Mass of M: 2.1 g

    Our new sample weighs 329 g

    We may solve this by a rule of three:

    44.9 g of sample contain 2.1 g of M

    329 g of sample will contain (329. 2.1) / 44.9 = 15.38 g
  2. 30 January, 16:52
    0
    In a 329 grams mineral, we have 15.4 grams of metal M

    Explanation:

    Step 1: Data given

    Mass of the sample = 44.9 grams

    The mineral contains: 2.1 grams of M

    Step 2: Calculate mass % of M

    mass % of M = (mass M / total mass sample) * 100 %

    mass % of M = (2.1 grams / 44.9 grams) * 100 %

    mass % of M = 4.677 %

    Step 3: Calculate the mass of M in a 329 grams

    Mass % = (4.677 grams / 100 %) * 329 grams

    Mass % = 0.04677 * 329 grams

    Mass % = 15.4 grams

    In a 329 grams mineral, we have 15.4 grams of metal M
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