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28 May, 05:33

Combustion analysis of a hydrocarbon produced 33.01 g co2 and 27.02 g h2o. calculate the empirical formula of the hydrocarbon.

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  1. 28 May, 09:26
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    The empirical formula of hydrocarbon is CH4

    explanation

    Hydrocarbon contain both hydrogen (H) and carbon (C)

    calculate the mass of C and H

    mass of C from CO2 = 12/44x33.01=9.003 g

    mass of H from H2O = 2/18 x27.02 = 3.002 g

    find the number of moles of C and H

    mole=mass/molar mass

    moles of C = 9.003g/12g/mol=0.7503 moles

    moles of H = 3.002g / 1g/mol = 3.002 moles

    find the mole ratio of each element by dividing each mole with smallest number of mole (0.7503 moles)

    that is C=0.7503/0.7503=1

    H=3.002/0.7503=4

    therefore the empirical formula = CH4
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