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29 December, 13:25

For the reaction represented by the equation Pb (NO3) 2 + 2KI → PbI2 + 2KNO3, how many moles of lead iodide are produced from 3.0 moles of potassium iodide when Pb (NO3) 2 is in excess?

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Answers (2)
  1. 29 December, 13:58
    0
    1.5mole

    Explanation:

    The equation for the reaction is given below:

    Pb (NO3) 2 + 2KI → PbI2 + 2KNO3

    From the equation,

    2moles of KI produced 1mole of PbI2.

    Therefore, 3moles of KI will produce = 3/2 = 1.5mole of PbI2.

    Therefore, 1.5mole of Pbl2 are produced
  2. 29 December, 17:10
    0
    1.5 moles of PbI2 will be produced

    Explanation:

    From the balanced chemical equation

    2 moles of KI yields 1mole of PBI2

    Then 3 moles of KI will yield 1.5 moles of PbI2 ...
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