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26 September, 20:35

You have 627 ml of 5.04 M HCl. Using a volumetric pipet, you take 229 ml of that solution and dilute it to 921 ml in a volumetric flask. Now you take 100.00 ml of that solution and dilute it to 192 ml in a volumetric flask. What is the concentration of hydrochloric acid in the final solution? Enter your answer numerically in units of M to three significant figures.

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  1. 26 September, 23:25
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    0.653

    Explanation:

    1)

    M1V1 = M2V2

    M1 = 5.04 M

    V1 = 229 mL (you take only this volume)

    V2 = 921 mL

    5.04*229 = M2 * 921

    M2 = (5.04*229) / 921 Molarity

    2)

    M1V1 = M2V2

    M1 = (5.04*229) / 921

    V1 = 100 mL

    V2 = 192 mL

    (5.04*229) / 921 * 100 = M2 * 192

    M2 = [ (5.04*229) / 921 * 100]/192 = 0.653 final molarity
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