The pka of hypochlorous acid is 7.530. a 54.0 ml solution of 0.114 m sodium hypochlorite (naocl) is titrated with 0.337 m hcl. calculate the ph of the solution

After the addition of 6.47 mL of 0.303 M HCl. Solution : - lets first calculate the moles of the NaOCl and HCl Moles = molarity * volume in liter Moles of NaOCl = 0.100 mol per L * 0.053 L = 0.0053 mol Moles of HCl = 0.303 mol per L * 0.00647L=0.00196