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22 February, 18:26

A balloon with a volume of 2.0 L at 25°C is placed

in a hot room at 35°C. The pressure on the balloon

is constant at 1.0 atm.

How does the volume of the balloon change after

moving it to the hot room?

+1
Answers (1)
  1. 22 February, 19:28
    0
    V₂ = 2.1 L

    Explanation:

    Given dа ta:

    Initial volume of balloon = 2.0 L

    Initial temperature = 25°C

    Final temperature = 35°C

    Final volume of balloon in hot room = ?

    Solution:

    Initial temperature = 25°C (25+273 = 298 K)

    Final temperature = 35°C (35+273 = 308 k)

    According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

    Mathematical expression:

    V₁/T₁ = V₂/T₂

    V₁ = Initial volume

    T₁ = Initial temperature

    V₂ = Final volume

    T₂ = Final temperature

    Now we will put the values in formula.

    V₁/T₁ = V₂/T₂

    V₂ = V₁T₂/T₁

    V₂ = 2.0 L * 308 K / 298 k

    V₂ = 616 L. K / 298 K

    V₂ = 2.1 L
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