A balloon with a volume of 2.0 L at 25°C is placed

in a hot room at 35°C. The pressure on the balloon

is constant at 1.0 atm.

How does the volume of the balloon change after

moving it to the hot room?

V₂ = 2.1 L

Explanation:

Given dа ta:

Initial volume of balloon = 2.0 L

Initial temperature = 25°C

Final temperature = 35°C

Final volume of balloon in hot room = ?

Solution:

Initial temperature = 25°C (25+273 = 298 K)

Final temperature = 35°C (35+273 = 308 k)

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 2.0 L * 308 K / 298 k

V₂ = 616 L. K / 298 K

V₂ = 2.1 L