1. A sample of oxygen has a volume of 2.1 L when the pressure is 375 torr, what is the volume when the pressure is 663 torr?

Answer: 1.2 Liters

Explanation:

Given that,

Original volume of oxygen V1 = 2.1 L

Original pressure of oxygen P1 = 375 torr

New pressure of oxygen P2 = 663 torr

New volume of oxygen V2 = ?

Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

375 torr x 2.1L = 663 torr x V2

787.5 torr L = 663 torr x V2

V2 = 787.5 torr L / 663 torr

V2 = 1.188L (Round the volume to the nearest tenth as in 1.2L)

Thus, the volume of oxygen is 1.2 liters when the pressure is 663 torr.