The element boron (B, atomic number 5 and atomic mass 11) is right above aluminum (Al, atomic number 13 and atomic mass 27) in the periodic table. How many more electrons does aluminum have than boron? Why?
There are 16 more electrons in aluminum because you subtract the atomic mass of boron from aluminum. 27-11=16
There are 8 more electrons in aluminum because you subtract the atomic number of boron from aluminum. 13-5=8
You can't determine how many more electrons aluminum has than boron from this information.
There are 14 more electrons in aluminum because you subtract the atomic number of aluminum from its atomic mass. 27-13=14
Answers (2)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The element boron (B, atomic number 5 and atomic mass 11) is right above aluminum (Al, atomic number 13 and atomic mass 27) in the periodic ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers
You Might be Interested in
Which part of a plant cell is responsible for converting light energy into chemical energy?
Answers (2)
How does an increase in temperature affect a chemical reaction?
Answers (1)
When sedimentary rock is exposed to heat and pressure what dose it change to
Answers (1)
A spoon of salt is added to water. Which of these will increase how fast the salt dissolves? Check all of the boxes that apply.
Answers (1)
Indicate whether each statement is true or false. Sort these statements into the proper categories. A) NaCl dissolves in water but not in benzene (C6zH6) because benzene is denser than water.
Answers (1)
New Questions in Chemistry
What is an example of making a qualified observation
Answers (1)
With respect to composition, how is the compound made from hydrogen and oxygen different from mixtures of these two elements?
Answers (1)
How should scientist respond when new evidence that challenges current is presented?
Answers (1)
Consider the following reaction, equilibrium concentrations, and equilibrium constant at a particular temperature. Determine the equilibrium pressure of H2. D2 (g) + H2 (g) ⇌ 2 HD (g) Kp = 1.80 P (D2) eq = 1.1 * 10-3 atm P (HD) eq = 2.7 * 10-3 atm
Answers (1)
Find δe for the change in state of 1.0 molh2o (l) at 79 ∘c to h2o (g) at 116 ∘c. the heat capacity of h2o (l) = 75.3 j/molk, heat capacity of h2o (g) = 25.0 j/molk, and the heat of vaporization of h2o is 40.7*103j/mol at 100 ∘c.
Answers (1)