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10 July, 17:40

156 grams of sodium sulfide, Na2S, is dissolved in

1000 mL of solution. Determine the molarity (M).

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Answers (2)
  1. 10 July, 21:09
    0
    M Na2S = 2 M

    Explanation:

    molarity (M) [=] mol/L sln

    ∴ mass Na2S = 156 g

    ∴ molar mass Na2S = 78.0452 g/mol

    ⇒ mol Na2S = (156 g) * (mol/78.0452 g) = 1.9988 mol ≅ 2 mol

    ∴ volume sln = 1000 mL = 1 L

    molarity (M):

    ⇒ M Na2S = 2 mol / 1 L

    ⇒ M Na2S = 2 M
  2. 10 July, 21:18
    0
    The molarity of the Na2S solution is 2.00 M

    Explanation:

    Step 1: Data given

    Sodium sulfide = Na2S

    Mass of sodium sulfide = 156.0 grams

    Molar mass of sodium sulfide (Na2S) = 78.0452 g/mol

    Volume = 1000 mL = 1.0 L

    Step 2: Calculate moles of sodium sulfide (Na2S)

    Moles Na2S = mass Na2S / molar mass Na2S

    Moles Na2S = 156.0 grams / 78.0452 g/mol

    Moles Na2S = 1.999 moles

    Step 3: Calculate molarity Na2S solution

    Molarity Na2S solution = moles Na2S / volume solution

    Molarity Na2S solution = 1.999 moles / 1.0 L

    Molarity Na2S solution = 1.999 M ≈ 2.00 M

    The molarity of the Na2S solution is 2.00 M
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