What mass of sodium sulfate is needed to make 2.5 L of 2.0 M solution?

A 120 g

B 150 g

C 180 g

D 710 9

E 750 g

D) 710 g

Step by Step:

Multiply 2.5 L by 2.0 M to solve for moles

2 mol/L • 2.5 L = 5 mol

Find formula weight of sodium sulfate

Na2SO4-142.04 g/mol

Na - 2 (22.99) = 45.98

S-32.06

O-4 (16) = 64

Multiply miles by formula weight

5 mole • 142.04 g/mol=710.2 g