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30 August, 08:06

A gas has a volume of 30 L at 105 kPa. What pressure is required to compress the gas to 21 L?

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  1. 30 August, 10:51
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    Answer: 150 kPa

    Explanation:

    Given that,

    Original volume of gas V1 = 30L

    Original pressure of gas P1 = 105 kPa

    New pressure of gas P2 = ?

    New volume of gas V2 = 21L

    Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law

    P1V1 = P2V2

    105 kPa x 30L = P2 x 21L

    3150 kPa L = P2 x 21L

    P2 = 3150 kPa L / 21 L

    P2 = 150 kPa

    Thus, 150 kPa of pressure is required to compress the gas
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