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19 August, 14:16

A chunk of aluminum weighing 19.7 grams and originally at 98.01 °C is dropped into an insulated cup containing 81.3 grams of water at 21.05 °C. Assuming that all of the heat is transferred to the water, the final temperature of the water is

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  1. 19 August, 15:36
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    T (final) = 35°C

    Explanation:

    Use ∑ (heat flows) = ∑q = 0

    q (Al) + q (H₂O) = (mcΔT) Al + (mcΔT) H₂O = 0

    [ (19.7g) (0.91cal/g°C) (T (f) - 98.01°C) ] + [ (81.3g) (1.00cal/g°C) (T (f) - 21.05°C) ] = 0

    Collecting terms and solving for T (f) = 35°C final mix temperature
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