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23 January, 19:10

How many moles of dipyrithione contain 6.3*1024 atoms of nitrogen?

Express your answer to two significant figures and include the appropriate units

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  1. 23 January, 19:39
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    5.2 moles dipyrithione contain 6.3 * 10^24 atoms of nitrogen

    Explanation:

    Step 1: Data given

    Dipyrithione = C10H8N2O2S2

    Number of Avogadro = 6.02 * 10^23

    Number of nitrogen atoms = 6.3 * 10^24 atoms

    Step 2: Calculate moles nitrogen

    Moles nitrogen = atoms nitrogen / number of Avogadro

    Moles nitrogen = 6.3 * 10^24 / 6.02 * 10^23

    Moles nitrogen = 10.47 moles

    Step 3: Calculate moles dipyrithione

    In 1 mol dipyrithione we 2 moles N

    For 10.47 moles N we have 10.47/2 = 5.2 moles dipyrithione

    5.2 moles dipyrithione contain 6.3 * 10^24 atoms of nitrogen
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