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17 June, 18:16

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Given the following reaction:

Mg (OH), + 2HCI - MgCl2 + 2H2O

How many grams of MigCl, will be produced from 16.0 g of Mg

d 11.0 g of HCI?

grams (round to three significant figures)

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  1. 17 June, 21:13
    0
    Mass = 14.3 g

    Explanation:

    Given dа ta:

    Mass of Mg (OH) ₂ = 16.0 g

    Mass of HCl = 11.0 g

    Mass of MgCl₂ = ?

    Solution:

    Chemical equation:

    Mg (OH) ₂ + 2HCl → MgCl₂ + 2H₂O

    Number of moles of Mg (OH) ₂:

    Number of moles = mass / molar mass

    Number of moles = 16.0 g / 58.3 g/mol

    Number of moles = 0.274 mol

    Number of moles of HCl:

    Number of moles = mass / molar mass

    Number of moles = 11.0 g / 36.5 g/mol

    Number of moles = 0.301 mol

    Now we will compare the moles of Mg (OH) ₂ and HCl with MgCl₂.

    Mg (OH) ₂ : MgCl₂

    1 : 1

    0.274 : 0.274

    HCl : MgCl₂

    2 : 1

    0.301 : 1/2*0.301 = 0.150

    The number of moles of MgCl₂ produced by HCl are less so it will limiting reactant.

    Mass of MgCl₂:

    Mass = number of moles * molar mass

    Mass = 0.150 * 95 g/mol

    Mass = 14.3 g
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