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29 September, 19:31

What is the theoretical mass of water produced from 10 moles of NaHCO3? NaHCO3 + CO2 + H2O

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  1. 29 September, 21:00
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    90g

    Explanation:

    Let us write a balanced equation for the reaction. NaHCO3 decompose to yield water as illustrated below:

    2NaHCO3-> Na2CO3 + CO2 + H2O

    Theoretical yield of water can be obtained as follow:

    From the equation,

    2 moles of NaHCO3 produced 1 mole of H2O.

    Therefore, 10 mole of NaHCO3 will produce = 10/2 = 5 moles of H2O.

    Now we shall convert 10 moles of H2O to grams to obtain the theoretical yield of water. This is illustrated below:

    Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

    Number of mole of H2O = 5 moles

    Mass of H2O = ?

    Mass = number of mole x molar Mass

    Mass of H2O = 5 x 18

    Mass of H2O = 90g.

    Therefore, the theoretical yield of water is 90g
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