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1 December, 00:14

A gas at 89.0 °C occupies a volume of 0.67 L. At what Celsius temperature will the volume increase to 15.9 L?

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  1. 1 December, 01:54
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    The answer to your question is T2 = 5755.8 °K

    Explanation:

    Data

    temperature 1 = 89 °C

    Volume 1 = 0.67L

    temperature 2 = ?

    Volume 2 = 15.9 L

    Process

    Use Charles' law to solve this problem

    V1/T1 = V2/T2

    -Solve for T2

    T2 = V2T1/V1

    -Convert temperature to °K

    temperature 1 = 89 + 273 = 362°K

    -Substitution

    T2 = (15.9 x 362) / 0.67

    -Simplification

    T2 = 5755.8 / 0.67

    -Result

    T2 = 5755.8 °K
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