A gas sample has volume 3.00dm3 at 101kPa. What will be the volume if the pressure is reduced to 14.2kPa?

V₂ = 21.3 dm³

Explanation:

Given dа ta:

Initial volume of gas = 3.00 dm³

Initial pressure = 101 Kpa

Final pressure = 14.2 Kpa

Final volume = ?

Solution;

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume

Now we will put the values in formula,

P₁V₁ = P₂V₂

101 Kpa * 3.00 dm³ = 14.2 Kpa * V₂

V₂ = 303 Kpa. dm³ / 14.2 Kpa

V₂ = 21.3 dm³