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7 October, 12:53

A balloon contains 0.950 mol of nitrogen gas and has a volume of 25.5 L. How many grams of N2 should be released from the balloon to bring the volume to 17.3 L

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  1. 7 October, 16:01
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    Mass released = 8.6 g

    Explanation:

    Given dа ta:

    Initial number of moles nitrogen = 0.950 mol

    Initial volume = 25.5 L

    Final mass of nitrogen released = ?

    Final volume = 17.3 L

    Solution:

    Formula:

    V₁/n₁ = V₂/n₂

    25.5 L / 0.950 mol = 17.3 L/n₂

    n₂ = 17.3 L * 0.950 mol/25.5 L

    n₂ = 16.435 L. mol / 25.5 L

    n₂ = 0.644 mol

    Initial mass of nitrogen:

    Mass = number of moles * molar mass

    Mass = 0.950 mol * 28 g/mol

    Mass = 26.6 g

    Final mass of nitrogen:

    Mass = number of moles * molar mass

    Mass = 0.644 mol * 28 g/mol

    Mass = 18.0 g

    Mass released = initial mass - final mass

    Mass released = 26.6 g - 18.0 g

    Mass released = 8.6 g
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