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2 November, 08:00

To how much water should 250 mL of 12 M hydrochloric acid be added to

produce a 4.0 M solution?

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Answers (1)
  1. 2 November, 11:51
    0
    500 mL water

    Explanation:

    M1V1 = M2V2

    M - molarity, V - volume of solution before adding water

    M1 = 12MV1 = 250 mL

    M2 = 4.0 M

    12M * 250 mL = 4.0*V2

    V2 = 12*250/4.0 = 750 mL of solution should become after adding water

    750 mL - 250 mL = 500 mL of water should be added
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