Ask Question
12 July, 14:29

Given the following balanced chemical equation:

Ca (OH) 2 (s) + 2HNO3 (aq) → Ca (NO) 3 (aq) + 2H2O (l)

How many grams of Ca (OH) 2 are required to neutralize 25.0 ml of 0.100 M HNO3?

+2
Answers (1)
  1. 12 July, 16:44
    0
    Mass of Ca (OH) ₂ required = 0.09 g

    Explanation:

    Given dа ta:

    Volume of HNO₃ = 25 mL (25/1000 = 0.025 L)

    Molarity of HNO₃ = 0.100 M

    Mass of Ca (OH) ₂ required = ?

    Solution:

    Chemical equation;

    Ca (OH) ₂ + 2HNO₃ → Ca (NO) ₃ + 2H₂O

    Number of moles of HNO₃:

    Molarity = number of moles / volume in L

    0.100 M = number of moles / 0.025 L

    Number of moles = 0.100 M * 0.025 L

    Number of moles = 0.0025 mol

    Now we will compare the moles of Ca (OH) ₂ with HNO₃ from balance chemical equation.

    HNO₃ : Ca (OH) ₂

    2 : 1

    0.0025 : 1/2*0.0025 = 0.00125

    Mass of Ca (OH) ₂:

    Mass = number of moles * molar mass

    Mass = 0.00125 mol * 74.1 g/mol

    Mass = 0.09 g
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Given the following balanced chemical equation: Ca (OH) 2 (s) + 2HNO3 (aq) → Ca (NO) 3 (aq) + 2H2O (l) How many grams of Ca (OH) 2 are ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers