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5 April, 02:57

A solution of acetic acid is prepared in water by adding 11.1 g of sodium acetate to 200 ml of water. The final ph is measured to be 6.5. What are the concentrations of acetate and acetic acid in solution?

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  1. 5 April, 03:24
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    Given buffer contains:

    Acetic acid: CH3COOH.

    Sodium Acetate : CH3COONa.

    Mass of CH3COONa taken = 11.1 g

    Molar mass of CH3COONa = 82.03 g/mol

    # moles of CH3COONa = 11.1g/82.03 g. mol-1 = 0.1353 moles

    Volume of water = 200 ml = 0.2 L

    Therefore, the initial concentration of CH3COONa = 0.1353/0.2 = 0.677 M

    Buffer pH = 6.5

    pKa (CH3COOH) = 4.76

    Based on Henderson-Hasselbalch equation:

    pH = pKa + log [CH3COONa]/[CH3COOH]

    Now, initially there is only 0.677 M CH3COONa. If 'x' is the concentration of the protonated species (i. e CH3COOH) formed, then the amount of CH3cooNa remaining = 0.677-x

    6.5 = 4.76 + log [0.677-x]/[x]

    x = 0.011 M

    i. e. [CH3COOH] = 0.011 m

    [CH3COONa] = 0.677-0.011 = 0.666 M
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