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27 July, 10:10

CCl2F2 (g) + 4H2 (g) → CH2F2 (g) + 2HCl (g)

What volume of hydrogen at 225atm and 33,5 °C would be required to react with 1 ton of CCl2F2?

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  1. 27 July, 10:35
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    3,383 Liters H₂ (g)

    Explanation:

    Given Rxn ...

    CCl₂F₂ (g) + 4H₂ (g) = > CH₂F₂ (g) + 2HCl (g)

    ? Vol H₂ (g) needed to react with 1 Ton CCl₂F₂ (g) at 33.5°C (=306.5K) & 225atm

    Rxn Ratio CCl₂F₂ (g) : H₂ (g) = > 1 mole CCl₂F₂ (g) to 4 moles H₂ (g)

    1 Ton CCl₂F₂ (g) = 2000 lbs CCl₂F₂ (g) = 908,000 grams CCl₂F₂ (g)

    908,000 grams CCl₂F₂ (g) = (908,000 grams / 120 grams/mole) = 7,567 moles CCl₂F₂ (g)

    7,567 moles CCl₂F₂ (g) requires 4 x 7,567 moles H₂ (g) = 30,267 moles H₂ (g)

    Using Ideal Gas Law = > P·V = n·R·T = > V = n·R·T/P

    P = 225 atm

    n = 30,267 moles H₂ (g)

    R = 0.08206 L·atm/mol·K

    T = 33.5°C = 306.5K

    ∴Vol H₂ (g) needed = (30,267 moles H₂ (g)) (0.08206L·atm/mol·K) (306.5K) / (225atm) = 3,383 Liters H₂ (g)
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