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5 May, 19:01

What is the rate law for the reaction that has the

following mechanism?

Step 1: NO (g) + NO (g) - N2O2 (g) (fast)

Step 2: N202 (g) + O2 (g) - 2NO2 (g) (slow)

rate = k[NO][N202]

rate = K[NO]2

rate = k[NO] [02]

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Answers (1)
  1. 5 May, 20:14
    0
    rate = k[NO] [02]

    Explanation:

    the N2O2 cancel because they are intermediates leaving 2NO + O2
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