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1 July, 02:25

10.00 mL of 0.10 M NaOH is added to 25.00 mL of 0.10 M HCl during a titration

Which expression shows how to determine the Ht

concentration of the solution now?

A. 0.0025/0.025

B. 0.0025/0.035

C. O. 0015/0.025

D. 0.0015/0.035

What is the pH of the solution after this addition?

(Write answer to two decimal places.)

pH =

+5
Answers (1)
  1. 1 July, 05:03
    0
    10 mL =.01 L.

    25 mL =.025 mL.

    10 mL of. 1 M NaOH will contain. 01 x. 1 =.001 moles

    25 mL of. 1M HCl will contain. 025 x. 1 =.0025 moles

    acid will neutralise and after neutralisation moles of acid remaining

    =.0025 -.001 =.0015 moles.

    Total volume =.01 +.025 =.035 L

    concentration of remaining HCl =.0015 /.035

    Option D is correct.

    =.042857 M

    = 42.857 x 10⁻³ M.

    pH = - log [42.857 x 10⁻³]

    = 3 - log 42.857

    = 3 - 1.632

    = 1.368.
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