A gas in a sealed container had its volume increased from 12.1 liters to 21.1 liters.

and heated from 241 K to 298 K. If the original pressure was 546 torn what would

be the final pressure in torr?

Question

Chemistry

Oakley

18 October, 04:29

A gas in a sealed container had its volume increased from 12.1 liters to 21.1 liters.

and heated from 241 K to 298 K. If the original pressure was 546 torn what would

be the final pressure in torr?

+1

Answers (1)

Know the Answer?

Precious Bautista · Answer 1

The answer to your question is P2 = 170.9 torr

Explanation:

Data

Volume 1 = 12.1 l Volume 2 = 21.1 l

Temperature 1 = 241 °K Temperature 2 = 298°K

Pressure 1 = 546 torr Pressure 2 = ?

Process

To solve this problem use the combined gas law.

P1V1/T1 = P2V2/T2

-Solve for P2

P2 = T1V1T2 / T1V2

-Substitution

P2 = (241 x 12.1 x 298) / (241 x 21.1)

-Simplification

P2 = 868997.8 / 5085.1

-Result

P2 = 170.9 torr

A gas in a sealed container had its volume increased from 12.1 liters to 21.1 liters.and heated from 241 K to 298 K. If the original pressure was 546 torn what wouldbe the final pressure in torr?

A gas in a sealed container had its volume increased from 12.1 liters to 21.1 liters.

and heated from 241 K to 298 K. If the original pressure was 546 torn what would

be the final pressure in torr?