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10 December, 13:29

Question 5

Determine the mass (in g) of oxygen (Mc = 32.00) that occupies a volume of 146.7 cm? at a pressure of

106.5 kPa and a temperature of 167 °C. Give the answer to 3 significant figures

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Answers (1)
  1. 10 December, 13:58
    0
    0.128 g

    Explanation:

    Given dа ta:

    Volume of gas = 146.7 cm³

    Pressure of gas = 106.5 Kpa

    Temperature of gas = 167°C

    Mass of oxygen gas = ?

    Solution:

    Volume of gas = 146.7 cm³ (146.7 / 1000 = 0.1467 L)

    Pressure of gas = 106.5 Kpa (106.5/101 = 1.1 atm)

    Temperature of gas = 167°C (167 + 273.15 = 440.15 K)

    PV = nRT

    P = Pressure

    V = volume

    n = number of moles

    R = general gas constant = 0.0821 atm. L / mol. K

    T = temperature in kelvin

    n = PV/RT

    n = 1.1 atm * 0.1467 L / 0.0821 atm. L / mol. K * 440.15 K

    n = 0.1614 / 36.14 / mol

    n = 0.004 mol

    Mass of oxygen:

    Mass = number of moles * molar mass

    Mass = 0.004 mol * 32 g/mol

    Mass = 0.128 g
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