To what volume must 480.0 mL of 3.50 M Cu (NO3) 2 be diluted to produce 2.10 M Cu (NO3) 2?

800 mL

Explanation:

This is a dilution question so we have to use the dilution formula

c1v1 = c2v2

Where c1 is the concentration and v1 is the volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

Substituting the values in the equation

3.50 M x 480.0 mL = 2.10 M x v2

v2 = 800 mL

A volume of 480.0 mL of 3.50 M solution should be diluted upto a volume of 800 mL to make a diluted copper nitrate solution of concentration 2.10 M