20 PTS! What is the volume of a gas at 90.0°C, if it occupies 1.41 L at 170°C?

1.72 L

Explanation:

Initial Temperature of the gas T = 90°+273 = 363 K

Initial Volume of the gas V1 = 1.41 L

Final temperature of the gas T2 = 170°c + 273 = 443 K

Final volume of the gas V2=?

Using Charles law;

V1/T1 = V2/T2

V1T2 = V2T1

V2 = V1T2/T1

V2 = 1.41*443/363

V2 = 1.72 L

The new volume of the gas is 1.72L

Explanation:

V1 = 1.41L

V2 = ?

T1 = 90°C = (90+273.15) K = 363.15K

T2 = 170°C = (170+273.15) K = 443.15K

To find the new volume V2 of the gas, we apply Charles law which states that the volume of a fixed mass of gas is directly proportional to its temperature provided that pressure remains constant.

V = KT, K = V1 / T1 = V2 / T2 = V3 / T3 ... = Vn / Tn

V1 / T1 = V2 / T2

Solve for V2,

V2 = (V1 * T2) / T1

V2 = (1.41 * 443.15) / 363.15

V2 = 1.72L

The new volume of the gas is 1.72L