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7 March, 09:02

How many ml of 0.0500 m cacn2 are needed to make 25.0 ml of 0.0150 m solution? The molar mass of cacn2 is 80.11 g/mol.

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  1. 7 March, 11:35
    0
    = 7.50 mL

    Explanation:

    m1v1=m2v2

    In this case;

    m1=0.05

    m2=0.015 and

    v2=25.00mL

    Therefore;

    (.0500M) (v1) = (25.00mL) (.0150M)

    V1 = ((25.00mL) (0.0150M)) / 0.0500 M

    = 7.50 mL
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