How many grams of NaCl are required to make 150.0mL of a 5.000 m solution

The number of grams of NaCl required to make 150.0 ml of a 5.000m solution is 43.875 grams

calculation

Step 1: calculate moles of NaCl

moles = molarity x volume in liters

volume in liters = 150.0 ml/1000 = 0.15 l

moles is = 5.000mol/l x0.15 l = 0.75 moles

Step2 : find mass

mass = moles x molar mass

molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

mass = 0.75 moles x58.5 g/mol = 43.875 grams