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2 January, 23:46

What is the amount of heat absorbed

when the temperature of 75 grams

of water increases from

20° C to 35°C

+3
Answers (1)
  1. 3 January, 01:28
    0
    1125 cal

    4707 Joules

    Explanation:

    This question can be solved by the calorimetry formula:

    Q = m. C. ΔT

    ΔT = Final T° - Initial T°

    C = Specific heat of the compound

    In this case our compound is water; the specific heat is 1 cal/g°C

    m = mass

    We replace dа ta: Q = 75 g. 1 cal/g°C (35°C - 20°C)

    Q = 1125 cal

    We can give this value in units of Joules

    Let's do the conversion: 1 cal = 4.184 J

    1125 cal. 4.184 J / 1 cal = 4707 Joules
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