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11 October, 08:06

How much pressure is required to compress 1L volume of air at 1atm pressure to 0.5L

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  1. 11 October, 11:26
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    p2 = 2atm

    Explanation:

    using Boyle's law

    p1 x v1 = p2 x v2

    v1 = 1L

    p1 = 1 atm

    p2=?

    v2=0.5L

    substitute;

    1 x 1 = p2 x 0.5

    p2 = (1 x 1) / 0.5

    p2 = 2atm
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