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27 January, 13:41

1

Determine the amount of heat (q) in joules that is released when 20.0 grams of water is cooled from 85˚C to 5˚C. Remember that the specific heat of water is 4.18 J/g˚C.

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  1. 27 January, 17:32
    0
    -6688 J

    Explanation:

    So for this question we have to use equation q = (m) (c) (deltaT)

    Mass=20.0 grams

    C=4.18 J/g

    delta T = final-initial = 5-85=-80

    q = (20.0) (4.18) (-80)

    q=-6688 J
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